How to count number of digits ?

The good approach will be to use log10 Time complexity O(1) Space complexity O(1) . The number of digits in an integer = the upper bound of log10(n).
Example: log10(12345.0)) = > 4.091491094267951 so we have to use 4+1

print ("count the number of digits = ", Int(log10(12345.0))+1)// prints 5

Read more about Logarithm here

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